Answer:
The value of percentile at start is 3.01 while that of now is 55.17.
Step-by-step explanation:
For the year the 2009 the value is given as 88.1 with a standard deviation of 1.6
Now for the value of 85.1 as of 2000-2009 the z score is given as
[tex]z=\frac{x-\mu}{\sigma}\\z=\frac{85.1-88.1}{1.6}\\z=-1.88[/tex]
For this value of z, the P(z<x) is given as 0.0301. The corresponding percentile is 3.01.
Now for the value of 88.3 for 2010-2018, the z value is
[tex]z=\frac{x-\mu}{\sigma}\\z=\frac{88.3-88.1}{1.6}\\z=0.13[/tex]
For this value of z, the P(z<x) is given as 0.5517 The corresponding percentile is 55.17.
The population between these two percentiles is given as 55.17-3.01 which given the value as 52.16.