Answer:
The motor inertia is 7.958 X 10⁻² kg.m²
Explanation:
To determine the motor inertia, the following formula applies.
Neglecting the damping effect,
[tex]T = \frac{J}{9.55}.\frac{\delta n}{\delta T}[/tex]
Where;
T is the constant torque applied to the motor = 5Nm
J is the motor inertia = ?
δn is the change in angular speed of the motor = 1800 r/min
δT is change in time of the unloaded motor from rest = 3 sec
[tex]J = \frac{9.55* \delta T* T}{\delta n}[/tex]
[tex]J = \frac{9.55* 3* 5}{1800}[/tex] = 0.07958 kg.m² = 7.958 X 10⁻² kg.m²
Therefore, the motor inertia is 7.958 X 10⁻² kg.m²