A constant torque of 5 Nm is applied to an unloaded motor at rest at time t ¼ 0. The motor reaches a speed of 1800 rpm in 3 s. Assuming the damping to be negligible, calculate the motor inertia.

Respuesta :

Answer:

The motor inertia is 7.958 X 10⁻² kg.m²

Explanation:

To determine the motor inertia, the following formula applies.

Neglecting the damping effect,

[tex]T = \frac{J}{9.55}.\frac{\delta n}{\delta T}[/tex]

Where;

T is the constant torque applied to the motor = 5Nm

J is the motor inertia = ?

δn is the change in angular speed of the motor = 1800 r/min

δT is change in time of the unloaded motor from rest = 3 sec

[tex]J = \frac{9.55* \delta T* T}{\delta n}[/tex]

[tex]J = \frac{9.55* 3* 5}{1800}[/tex] = 0.07958 kg.m² = 7.958 X 10⁻² kg.m²

Therefore, the motor inertia is 7.958 X 10⁻² kg.m²