Of the last 100 customers entering a computer shop, 25 have purchased a computer. If the classical method for computing probability is used, the probability that the next customer will purchase a computer is

a. .75
b. 1.00
c. .25
d. .50

___ The answer is apparently .50 but i am not understanding why that is so, wouldn't it be .25? Or is it that there is a option for the customer to buy or not buy so it makes it 50% so 50/100? I'm not sure...

Respuesta :

Answer:

Yes, the answer is 0.5.

Step-by-step explanation:

The question only try to trick you. The concept here is not the probability of picking from the sample of buying customers. It's simply testing your understanding about the sample space of the event.

By sample space, we mean the list of all possible outcome from a probability event. For this event, there is only two possibilities:

1. The customer buys a computer

2. The customer did not buy a computer.

That is,

Sample space = {buy, not buy}

The probability the next customer will buy or not buy is 50:50. This is because, every customer (whether buying or not buying) is treated a customer! So, next customer buy = 1/2 = 0.5. or not buying = 1/2 = 0.5.

Although, the odds of buying is 0.25!

If the classical method for computing probability is used, and some assumptions are made, the probability that the next customer will purchase a computer is given by: Option d: 0.50

Which pair of events are called independent events?

When one event's occurrence or non-occurrence doesn't affect occurrence or non-occurrence of other event, then such events are called independent events.

Symbolically, we have:

Two events A and B are said to be independent iff we have:

[tex]P(A \cap B) = P(A)P(B)[/tex]

Thus, from the chain rule of probability, we get

[tex]P(A|B) = P(A)\\ P(B|A) = P(B)[/tex]

(assuming A and B are independent events)

Each customer entering a computer shop end up doing one of two things. Either that customer buys a computer (assuming customer buys single computer)(lets call it success), or not(lets call it failure).

For this case, we assume 2 things.

1. Probability of buying a computer doesn't depend on previous number of buyers(independence of events).

2. Probability of buying or not buying is same, which means, both can occur equally probably.

Since there are only two outcomes for a customer entered in computer shop, and they are from

{buys a computer, doesn't buy a computer}

And since each are equally probable, let their probability be 'x'

Then, as sum of probability of all events is 1, therefore,

P(customer buys a computer) + P( customer does't buy a computer) = 1

or

[tex]x + x =1\\2x = 1\\x = 0.5[/tex]

Therefore, if the classical method for computing probability is used, and some assumptions are made, the probability that the next customer will purchase a computer is given by: Option d: 0.50

Learn more about probability here:

brainly.com/question/1210781