This is an incomplete question, here is a complete question.
The bulk modulus for bone is 15.0 (GPa). If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.130% of their original volume?
Answer : The change in pressure will be, [tex]1.95\times 10^7Pa[/tex]
Explanation : Given,
Bulk modulus = [tex]15.0GPa=15.0\times 10^9Pa[/tex]
Change in volume = 0.130 % of original volume
Let the original volume be, V
So, Change in volume = [tex]\frac{0.130}{100}\times V[/tex]
Formula used for change in pressure is:
[tex]\Delta P=\beta \frac{\Delta V}{V}[/tex]
Now put all the given values in this formula, we get:
[tex]\Delta P=(15.0\times 10^9Pa)\times \frac{(\frac{0.130}{100}\times V)}{V}[/tex]
[tex]\Delta P=1.95\times 10^7Pa[/tex]
Thus, the change in pressure will be, [tex]1.95\times 10^7Pa[/tex]
