Explanation:
The function is [tex]h(t)=-16 t^{2}+98[/tex]
To graph the function, let us find the coordinates of the function [tex]h(t)=-16 t^{2}+98[/tex]
For [tex]t=-2[/tex],
[tex]\begin{aligned}h(t) &=-16(-2)^{2}+98 \\&=-16(4)+98 \\&=-64+98 \\&=34\end{aligned}[/tex]
The ordered pair is [tex](-2,34)[/tex]
For [tex]t=-1[/tex],
[tex]\begin{aligned}h(t) &=-16(-1)^{2}+98 \\&=-16(1)+98 \\&=-16+98 \\&=82\end{aligned}[/tex]
The ordered pair is [tex](-1,82)[/tex]
For [tex]t=0[/tex],
[tex]\begin{aligned}h(t) &=-16(0)^{2}+98 \\&=98\end{aligned}[/tex]
The ordered pair is [tex](0,98)[/tex]
For [tex]t=1[/tex],
[tex]\begin{aligned}h(t) &=-16(1)^{2}+98 \\&=-16(1)+98 \\&=-16+98 \\&=82\end{aligned}[/tex]
The ordered pair is [tex](1,82)[/tex]
For [tex]t=2[/tex],
[tex]\begin{aligned}h(t) &=-16(2)^{2}+98 \\&=-16(4)+98 \\&=-64+98 \\&=34\end{aligned}[/tex]
Thus, plotting these ordered pairs we get the graph of the function. The image of the graph is attached below.
