There are 32 pennies and 24 nickels in jar
Solution:
Let "n" be the number of nickels
Let "p" be the number of pennies
1 penny = 0.01 dollar
1 nickel = 0.05 dollar
There are 56 coins in the jar in all
Therefore,
number of nickels + number of pennies = 56
n + p = 56 ----------- eqn 1
The total value of coins is $ 1.52
Thus we frame a equation as:
number of nickels x 0.05 + number of pennies x 0.01 = 1.52
[tex]n \times 0.05 + p \times 0.01 = 1.52[/tex]
0.05n + 0.01p = 1.52 -------- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
n = 56 - p ------ eqn 3
Substitute eqn 3 in eqn 2
0.05(56 - p) + 0.01p = 1.52
2.8 - 0.05p + 0.01p = 1.52
0.04p = 2.8 - 1.52
0.04p = 1.28
Divide both sides by 0.04
p = 32
Substitute p = 32 in eqn 3
n = 56 - 32
n = 24
Thus there are 32 pennies and 24 nickels in jar
