Answer:
Heat energy (Q) added is 3150 (J) .
Explanation:
Given:
Mass of the aluminum = 0.5 kg
Change in temperature = 7°C
According to the question :
Heat energy (Q) is added up.
We have to find the equation with correct values.
We know that,Q = mCΔT m is the mass,C is the specific heat and T is the change in temperature.
Specific heat of aluminum = 900 (J/kg °C)
Plugging the values,we have :
⇒ [tex]Q=mC\Delta T[/tex]
⇒ [tex]Q = 0.5\times 900\times 7[/tex]
⇒ [tex]Q= 3150[/tex] Joules (J)
So the heat energy added (Q) = 3150 Joules.
