Answer
given,
initial speed of boat, u = 0 m/s
acceleration of the boat, a = 0.21 m/s²
distance,s = 280 m
a) using equation of motion
v² = u² + 2 a s
v² = 0² + 2 x 0.21 x 280
v = √117.6
v = 10.84 m/s
Final speed of the boat is equal to 10.84 m/s
b) again using equation of motion
v = u + a t
10.84 = 0 + 0.21 x t
0.21 t = 10.84
t = 51.62 s
time taken by the boat to travel the distance is equal to 51.62 s.
