Explanation:
We know that that the range of the ball on the earth
[tex]R_{earth}=\frac{v_o^2sin2\theta}{g_{earth}}[/tex]
therefore, range of the ball on moon
[tex]R_{moon}=\frac{v_o^2sin2\theta}{g_{moon}}[/tex]
[tex]R_{moon}=\frac{v_o^2sin2\theta}{g_{earth}/12}[/tex]
therefore,
[tex]R_{moon}=6R_{earth}[/tex]
Therefore, the range of ball will be 6 times on the moon than that on earth
