Answer:
1.32 × 10⁻⁹ N, - 1.32 × 10⁻⁹ N
Explanation:
distance between the charges r ₀ = 0.46 nm + 0.131 nm = 0.591 nm = 0.591 × 10⁻⁹ m
Using Coulomb's law,
Force of attraction = (Z₁)(Z₂)q² / ( 4 πε₀r₀²) where
Z₁ = valency of divalent = +2
Z₂ = valency of monovalent = -1
ε₀ = 8.85 × 10⁻¹² C/ (Nm²)
Fa = (1 × 2 × ( 1.602 × 10⁻¹⁹ C)²) / (4 π ( 8.85 × 10⁻¹² C/Nm² ) ( 0.591 × 10⁻⁹ m)² )
Fa = 1.32 × 10⁻⁹ N
b) Force of repulsion = force of attraction = - 1.32 × 10⁻⁹ N at equilibrium
