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The triangular plate is xed at its base, and its apex A is given a horizontal displacement of 5 mm. Determine the average normal strain ϵx′ along the x′ axis. Determine the average normal strain ϵx0 along the x' axis.

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Hashirriaz830

Answer:

[tex]E x'[/tex]=[tex]8.84*10^{-3}[/tex] mm/mm

Explanation:

To determine normal strain ex' for x' a.xis.

Normal strain is the ratio of the length of the element before and after deformation.  

it is necessary to determine the distances between points before and after deformation.  

We calculate the distance between points C and A.

 CA = 800*cos45° = 565.68542 mm

We calculate the distance between points C and A'.

CA' = 800*cos45° +5 = 570.68542 mm

[tex]E x'[/tex]= [tex]\frac{CA' - CA}{CA}[/tex]...............(1)

putting the values in eq (1)

[tex]E x'[/tex]=[tex]8.84*10^{-3}[/tex] mm/mm

note:

following diagram is attached

Ver imagen Hashirriaz830

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