Answer:
The time save by Simpson is 25.8 minutes.
Explanation:
Given that,
Velocity of the car, v = 48 km/h
Distance covered by the car, d = 144 km
Let t is the time taken by the car. Speed of an object is given by distance covered per unit time. It is given by :
[tex]v=\dfrac{d}{t}[/tex]
[tex]t=\dfrac{d}{v}[/tex]
[tex]t=\dfrac{144\ km}{48\ km/h}[/tex]
t = 3 hours
If the velocity is increased to 56 km/h to the east. Time taken is given by :
[tex]t'=\dfrac{144\ km}{56\ km/h}[/tex]
t' = 2.57 seconds
The time save by Simpson increasing his average velocity is given by :
[tex]\Delta t=t-t'[/tex]
[tex]\Delta t=3-2.57[/tex]
[tex]\Delta t=0.43\ hours[/tex]
or
[tex]\Delta t=25.8\ min[/tex]
So, the time save by Simpson is 25.8 minutes. Hence, this is the required solution.
The time saved is 24 minutes.
Initially we are told that;
Speed of the car = 48.0 km/h
Distance covered = 144 km
We know that;
Speed = Distance/time
Time taken = Distance/speed = 144 km/48.0 km/h = 3 hours
Later;
Distance covered = 144 km
Speed = 56.0 km/h
Time taken = Distance/speed = 144 km/56.0 km/h = 2.6 hours
Time saved = 3 hours - 2.6 hours = 0.4 hours or 24 minutes
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