Answer:
(a) 95m
(b) -2.11m/s^2
(c) 9.5s
Explanation:
(a). out of remaining 105m, for initial 0.5s I travel with constant speed:
distace covered = 0.5s * 20m/s = 10m
it means that I am 105-10 = 95m away from the intersection
(b) we apply the second equation of motion
v^2 - u^2 = 2*a*s
so s = 95 m
u = initial velocity = 20 m/s
v = final velocity = 0 m/s ( comes to rest)
0^2 - 20^2 = 2*a*95
solving for 'a'
a = -2.11 m/s^2
(c)
v-u = at
0 - 20 = -2.11*t
solving for time t
t = 9.5s