Answer:
Number of electrons, [tex]n=3.87\times 10^8\ electrons[/tex]
Explanation:
Given that,
Charge on the fly, [tex]q=62\ pC=62\times 10^{-12}\ C[/tex]
Let n is the number of electrons lose to the surface it is walking across. It is case of quantization of electric charge. It is given by :
[tex]q=ne[/tex]
[tex]n=\dfrac{q}{e}[/tex]
[tex]n=\dfrac{62\times 10^{-12}}{1.6\times 10^{-19}}[/tex]
n = 387500000 electrons
or
[tex]n=3.87\times 10^8\ electrons[/tex]
So, there are [tex]3.87\times 10^8[/tex] electrons. Hence, this is the required solution.
