Respuesta :

Answer:

42.75m

Explanation:

8550 = mgh

8550 =20×10×h

h=8550/200

=42.75m

onyebuchinnaji

The height of the bell hanging at the top of a tower is 43.62 m.

The given parameters;

  • potential energy of the bell, P.E = 8550 J
  • mass of the bell, m = 20 kg

The height of the bell is determined by using gravitational potential energy formula as shown below;

P.E = mgh

where;

h is the height of the bell

[tex]h = \frac{P.E}{mg} \\\\h = \frac{8550}{20 \times 9.8} \\\\h = 43.62 \ m[/tex]

Thus, the height of the bell hanging at the top of a tower is 43.62 m.

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