Answer:
The car's displacement during this time is 25.65 meters.
Explanation:
Given that,
Final velocity of the car, v = 4.5 m/s
Deceleration of the car, [tex]a=-2.7\ m/s^2[/tex]
Let u is the initial speed of the car. It is given by :
[tex]v=u+at[/tex]
[tex]u=v-at[/tex]
[tex]u=4.5-(-2.7)\times 3[/tex]
u = 12.6 m/s
Let d is the car's displacement during this time. It can be calculated using second equation of motion as :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
[tex]d=12.6\times 3+\dfrac{1}{2}\times (-2.7)\times 3^2[/tex]
d = 25.65 meters
So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.
