Answer:
The magnitude of the force is 34.59 N.
Explanation:
Given that,
Inside pressure [tex]P_{in}= 1.90\times10^{5}\ Pa[/tex]
Area [tex]A=3.90\times10^{-4}\ m^2[/tex]
Outside pressure = 1 atm
We need to calculate the magnitude of the force
Using formula of force
[tex]F_{net}=F_{in}-F_{out}[/tex]
[tex]F_{net}=(P_{in}-P_{out})A[/tex]
Where, [tex]P_{in}[/tex] =inside Pressure
[tex]P_{out}[/tex] =outside Pressure
A = area
Put the value into the formula
[tex]F_{net}=(1.90\times10^{5}-1.013\times10^{5})3.90\times10^{-4}[/tex]
[tex]F_{net}=34.59\ N[/tex]
Hence, The magnitude of the force is 34.59 N.