Ranking from lowest to highest gravity: Pair 2 < Pair 4 < Pair 1 < Pair 3
Explanation:
The question is incomplete: find the missing table in attachment.
The magnitude of the gravitational force between two objects is given by the equation:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
Let's now rewrite the gravitational force between each of the 4 pairs:
1)
[tex]F=G\frac{(1M_E)(1M_S)}{(1AU)^2}=G\frac{M_EM_S}{AU^2}[/tex]
2)
[tex]F=G\frac{(1M_E)(2M_S)}{(2AU)^2}=\frac{1}{2}G\frac{M_EM_S}{AU^2}[/tex]
3)
[tex]F=G\frac{(2M_E)(1M_S)}{(1AU)^2}=2G\frac{M_EM_S}{AU^2}[/tex]
4)
[tex]F=G\frac{(4M_E)(2M_S)}{(3AU)^2}=\frac{8}{9}G\frac{M_EM_S}{AU^2}[/tex]
Therefore, we can rank the pairs from the lowest force of gravity to the highest force of gravity as follows:
Pair 2 < Pair 4 < Pair 1 < Pair 3
Learn more about gravity:
brainly.com/question/1724648
brainly.com/question/12785992
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