Respuesta :
Answer:
(D). The electric flux is changed if the point charge is moved to just outside the sphere.
Explanation:
A point charge placed at the center of a spherical Gaussian surface with radius r, the electric field has the same magnitude at every point of the sphere and is directed outward.
The electric flux Ф is then just the electric field E times the area of the sphere A.
Ф = EA
Area of sphere = 4πr²
Ф = E*4πr² [tex]= \frac{Q}{4\pi \epsilon r^2} *4\pi r^2 = \frac{Q}{\epsilon}[/tex]
Gauss's law of electricity, states that the electric flux through a closed surface with electric charge inside, just depends on the net charge enclosed in the surface and does not depend the shape or size of the surface.
From the law above;
- option A and B are out because electric flux does not depend on shape or size of the surface. It depends only on charge enclosed by the surface.
- Option C is also out since the charge is still inside the surface, the flux will not change.
- Option E is out as well because electric flux depends on the charge enclosed by the surface and doesn't depend on the charge outside another sphere.
However, option D stands out, because if the point charge is removed from the inside to outside the sphere, the flux will change.
The electric flux depends on the magnitude of the charge.
Option D is the correct statement. The electric flux is changed "if the point charge is moved to just outside the sphere".
What is electric flux?
The electric flux is defined as a property of an electric field that is the number of electric field lines that intersect a given area.
Given that a point charge is placed at the center of a spherical Gaussian surface.
Let's consider that r is the radius of the sphere and electric field E has the same magnitude at every point of the sphere and is in the outward direction. A is the area of the sphere.
The electric flux is given,
[tex]\phi = EA[/tex]
[tex]\phi = \dfrac {q}{4\pi \epsilon r^2}\times 4\pi r^2[/tex]
[tex]\phi = \dfrac {q}{\epsilon}[/tex]
According to Gauss's law of electricity, the electric flux through a closed surface with an electric charge placed inside depends on the net charge enclosed in the surface and does not depend on the shape or size of the surface.
Hence Option D is the correct statement. The electric flux is changed "if the point charge is moved to just outside the sphere".
To know more about the electric flux, follow the link given below.
https://brainly.com/question/7944455.