You have a 12 sided cube that is numbered from 1 to 12. What is the probability of rolling a 5?
50%
NEXLOUESTION
ASKERUDD
TURN

Respuesta :

Answer:

[tex]p(E)=\frac{1}{12}[/tex]

Explanation:

Given:

Side of the cube = 12

event = 5

Solution:

Using probability formula.

[tex]p(E)=\frac{n(E)}{n(S)}[/tex]

Where:

p(E) = Probability of an event

n(E) = Favourable event

n(S) = Sample space

Sample space of a 12 sided cube that is numbered from 1 to 12.

Sample space = {1,2,3,4,5,6,7,8,9,10,11,12}

[tex]n(S)=12[/tex]

Favourable event = {5}

[tex]n(E) = 1[/tex]

So the probability of rolling a 5.

[tex]p(E)=\frac{1}{12}[/tex]

Therefore, the probability of rolling a cube for event 5 is [tex]p(E)=\frac{1}{12}[/tex]