meggie98
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Please help with my homework

Solve the given triangles by finding the missing angle in the other side lengths.

Please help with my homework Solve the given triangles by finding the missing angle in the other side lengths class=

Respuesta :

Hrishii

Step-by-step explanation:

[tex] \angle \: A + \angle \: B + \angle \: C = 180 \degree \\ \therefore \: 18 \degree + \angle \: B + 140 \degree = 180 \degree \\ \therefore \: \angle \: B + 158 \degree = 180 \degree \\ \therefore \: \angle \: B = 180 \degree - 158 \degree \\ \huge \red{ \boxed{\therefore \: \angle \: B = 22 \degree}}[/tex]

The user @Hrishii is correct about the value of angle B.

Once you know all three angles, you can use the law of sines to find the missing sides.

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Let's use the law of sines to find side b

b/sin(B) = a/sin(A)

b/sin(22) = 1/sin(18)

b = sin(22)*1/sin(18)

b = 1.21225240111352

b = 1.21  rounding to two decimal places

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Repeat for side c

c/sin(C) = a/sin(A)

c/sin(140) = 1/sin(18)

c = sin(140)*1/sin(18)

c = 2.08010440004024

c = 2.08  rounding to two decimal places

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The fully solved triangle is

A = 18 degrees

B = 22 degrees

C = 140 degrees

a = 1

b = 1.21

c = 2.08

decimal values are approximate

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