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a 0.973 mole sample of helium gas at 25 degrees celsius filled a ballon to a volume of 3.87 L. what is the pressure of the ballon?

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Answer:

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Explanation:

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samueladesida43

6.15 atm

The ideal gas law equation is given as:

PV = nRT

Where;

P = pressure of the gas (atm)

V = volume of the gas (L)

n = number of moles of gas (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information given in this question;

P = ?

V = 3.87 L

n = 0.973 mol

T = 25°C = 25 + 273 = 298K

Using the formula; PV = nRT

P × 3.87 = 0.973 × 0.0821 × 298

3.87P = 23.81

P = 23.81 ÷ 3.87

P = 6.15atm

Hence, the pressure of the balloon at the given volume and temperature is 6.15 atm.

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