Respuesta :
Step-by-step explanation:
[tex]\int\sin x\ dx=-\cos x+C\\\\\text{because}\ \dfrac{dx}{dy}(-\cos x+C)=-(-\sin x)=\sin x[/tex]
Step-by-step explanation:
[tex]\int\sin x\ dx=-\cos x+C\\\\\text{because}\ \dfrac{dx}{dy}(-\cos x+C)=-(-\sin x)=\sin x[/tex]