A telephone pole is 15 meters tall and a pigeon is standing on the ground 8 meters from the pole. If the pigeon flies from where it is standing to the top of the telephone pole, how far will it fly?

Respuesta :

Step-by-step explanation:

[tex] {a }^{2} + {b}^{2} = {c}^{2} \\ {15}^{2} + {8}^{2} = {c}^{2} \\ 225 + 64 = {c}^{2} \\ \sqrt{289} = {c}^{2} \\ 17 = c[/tex]

[tex]H^2 = 15^2 + 8^2[/tex]Pigeon will fly the length of:

17 m

Find the distance

In the given Right-Angled Triangle Situation,

Distance between Pole base and Pigeon's Position on the ground [tex]= 8 meters[/tex].

This is the base of the triangle.

Height of telephone pole [tex]= 15 meters[/tex]

For Hypotenuse Solving,

by Pythagoras Theorem:

[tex]Hypotenuse^2[/tex] [tex]= Base^2[/tex] [tex]+ Height^2[/tex]

[tex]H^2 = 15^2 + 8^2[/tex]

[tex]H^2 = 65 + 225[/tex]

[tex]H^2 = \sqrt{290}[/tex]

∵ [tex]Hypotenuse = 17[/tex]

To learn more about 'Pythagoras Theorem' here:

brainly.com/question/18151335