contestada

How many moles of glucose are present in 1.0 L of blood with a blood sugar (glucose) concentration level of 140 mg/dL?


([tex]C_{6}H_{12} O_{6}[/tex] and M= 180.16 g/mol)

Respuesta :

Answer:

0.0078 mole

Explanation:

Volume of Blood = 1.0 L

Sugar concentration in blood = 140 mg/dL

no. of moles of Glucose = ?

Molar mass of sugar (C₆H₁₂O₆) = 180.16 g/mol

Solution:

To find the concentration concentration of sugar in 1.0 liter blood, first we convert mg/dL to g/L

So,

As we know

10 dL = 1 L

1 dL = x L

do cross multiplication

x L = 1 dL x 1 L / 10 dL

x L = 0.1 L

So,

1 dL = 0.1 L

Now we hae to convert mg to gram

As we Know

1 mg = 0.001 g

So,

140 mg = 140 x 0.001 = 0.14 g

So we come to know abot the concentration of sugar in terms of g/L as follows

140 mg/dL = 0.14 g/ 0.1 L

So now we have to find total amount of sugar in one liter. As we know there is 0.14 g sugar in 0.1 L of blood then how much amount it will be in 1 L of blood.

Apply unity formula

              0.14 g sugar ≅ 0.1 L of blood

              X g sugar ≅ 1 L of blood

Do cross Multiplication

            X g sugar = 1 L x 0.14 g/ 0.1 L

             X g sugar = 1.4 g

So we have 1.4 g in 1 l of blood, now we will convert mass to moles.

Formula will be used

          no. of moles = mass in grams / molar mass . . . . . (1)

As we know

Molar mass of sugar (C₆H₁₂O₆) = 180.16 g/mol

put values in above equation 1

           no. of moles = 1.4 g / 180.16 g/mol

           no. of moles = 0.0078 mol

So,

1.0 L of blood contain 0.0078 moles of sugar.