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[BrO- ]initial is 0.56 M. 33 seconds later [BrO- ] is 0.14 M. What is the rate of change of [BrO- ] in M/s? (The brackets, [ ], indicate concentration, that is, molarity (M) or moles/liter.)

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dsdrajlin

Answer:

0.013 M/s

Explanation:

Given data

  • Initial concentration of BrO⁻: 0.56 M
  • Final concentration of BrO⁻: 0.14 M
  • Time (t): 33 s

Since the final concentration of BrO⁻ is lower than the initial concentration of BrO⁻, BrO⁻ is dissapearing. The rate of dissapearance of BrO⁻ is:

rBrO⁻ = - Δ [BrO⁻] / t

rBrO⁻ = - (0.14 M - 0.56 M)/ 33 s

rBrO⁻ = 0.013 M/s

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