Answer:
10.23 grams of sucrose should be added.
Explanation:
1.15 m means molality (moles of solute in 1kg of solvent)
1.15 moles of sucrose are contained in 1 kg of solvent (1000 g)
Let's determine the moles in our mass of solvent.
Firstly we convert the g to kg → 26 g . 1kg/1000g = 0.026 kg
m . mass (kg) = 1.15 mol/kg . 0.026kg → 0.0299 moles.
Finally we convert the moles to mass (mol . molar mass)
0.0299 mol . 342.3 g/mol = 10.23 g
Answer:
The mass of sucrose is 10.23 grams
Explanation:
Step 1: Data given
Mass of water = 26 grams = 0.026 kg (=solvent)
Molality = 1.15 m
Step 2: Calculate moles sucrose
molality = moles sucrose / mass water
1.15 = moles sucrose / 0.026 kg
moles sucrose = 1.15 *0.026
moles sucrose = 0.0299 moles
Step 3: Calculate mass of sucrose
mass sucrose = moles sucrose * molar mass sucrose
mass sucrose = 0.0299 moles *342.3 g/mol
mass sucrose = 10.23 grams
The mass of sucrose is 10.23 grams
