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Calculate the maximum force that a 0.2-in. diameter rod of Al2O3, having a yield strength of 35,000 psi, can withstand with no plastic deformation. Express your answer in both lbs and N.

Respuesta :

Answer:

F=бА

Explanation:

DATA:

б=35,000 psi

А=0.2

solution:

put values in formula:

=(35,000)(π/4)(0.2)²

=1100lb(in pounds)

for newton N

=(1100)(4.48N/lb)

=4891N

Eduard22sly

Given the data from the question, the maximum force that the 0.2 in. diameter rod of Al₂O₃ can withstand in lbs and N is:

A. The maximum force in lbs is 1099 lb

B. The maximum force in N is 4888.352 N

How to determine the area

  • Diameter (d) = 0.2 in
  • Radius (r) = d / 2 = 0.2 / 2 = 0.1 in
  • Pi (π) = 3.14
  • Area (A) =?

A = πr²

A = 3.14 × 0.1²

A = 0.0314 in²

A. How to determine the force

  • Pressure (P) = 35000 psi
  • Area (A) = 0.0314 in²
  • Force (F) =?

F = PA

F = 35000 × 0.0314

F = 1099 lb

B. How to determine the force in Newton (N)

  • Force (in lb) = 1099 lb
  • Force (in N) =?

1 lb = 4.448 N

Therefore,

1099 lb = 1099 × 4.448

1099 lb = 4888.352 N

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