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A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2.00 105 kg. Calculate the magnitude of the necessary lifting force.

Respuesta :

princessesther2011

Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

Force = mv^2/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

Cricetus

The lifting force will be "7.94×10⁵ N".

Given:

  • Speed, [tex]v = 123 \ m/s[/tex]
  • Radius, [tex]r = 3810 \ m[/tex]
  • Mass, [tex]m = 2\times 10^5 \ kg[/tex]

As we know,

→ [tex]Lifting \ force = \frac{mv^2}{2}[/tex]

By putting the values,

                          [tex]= \frac{2\times 10^5\times (123)^2}{3810}[/tex]

                          [tex]= 794173.2 \ N[/tex]

                          [tex]= 7.94\times 10^5 \ N[/tex]

Thus the approach above is correct.

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https://brainly.com/question/11688274

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