A mixture of krypton and methane gases, at a total pressure of 775 mm Hg, contains 4.77 grams of krypton and 2.38 grams of methane. What is the partial pressure of each gas in the mixture?

Respuesta :

Answer:

Partial pressure of Kr → 214.06 mmHg

Partial pressure of CH₄ → 560.5 mmHg

Explanation:

To determine partial pressure we can work with mole fraction.

Mole fraction = moles of gas / Total gas = Partial pressure gas /Total pressure

Let's determine the moles of each compound (mass / molar mass)

4.77 g / 83.80 g/mol = 0.0569 moles of Kr

2.38 g / 16 g/mol = 0.149 moles of CH₄

Total moles = 0.0569 + 0.149 → 0.206

Partial pressure of Kr → (0.0569/0.206) . 775 mm Hg = 214.06 mmHg

Partial pressure of CH₄ → (0.149/0.206) . 775 mm Hg = 560.5 mmHg