Answer:
9.62 L
Explanation:
Considering the temperature to be constant, then:
PV = constant.
At 8.0 mm below the surface, pressure would be:
P₁ = ρ g h+ P₀
where, ρ is the density, g is the gravitational acceleration, h is the depth and P₀ is the atmospheric pressure.
ρ = 1020 kg/m³ (density of sea water)
P₁ = 1020 kg/m³ ×9.8 m/s²× 8.0 ×10⁻³ m+ 1.01 ×10⁵ Pa
P₁=79.968 + 1.01 ×10⁵ Pa = 1.8×10⁵ Pa
P₁V₁ = P₂V₂
At the surface, P₂ = P₀
V₂ = ( 1.8×10⁵ Pa)(5.4L) /(1.01 ×10⁵ Pa)
V₂ = 9.62 L
