Answer:
Neil has left with [tex]1\frac{1}{30}\ gallons[/tex] of paint.
Step-by-step explanation:
Given:
Amount of paint in can 1 = [tex]\frac{1}{3}\ gallon[/tex]
Amount of paint in can 2 = [tex]\frac{1}{5}\ gallon[/tex]
Amount of paint in can 3 = [tex]\frac{1}{2}\ gallon[/tex]
We need to find the amount of paint left with Neil.
Solution:
No we can say that;
the amount of paint left with Neil is equal to sum of Amount of paint in can 1,Amount of paint in can 2 and Amount of paint in can 3.
framing in equation form we get;
the amount of paint left with Neil = [tex]\frac{1}{3}+\frac{1}{5}+\frac{1}{2}[/tex]
Now to solve this we need to make the denominator common using LCM.
the amount of paint left with Neil = [tex]\frac{1\times 10}{3\times10}+\frac{1\times6}{5\times6}+\frac{1\times15}{2\times15}=\frac{10}{30}+\frac{6}{30}+\frac{15}{30}[/tex]
Now we have the denominator same so we will solve the numerator;
the amount of paint left with Neil = [tex]\frac{10+6+15}{30}= \frac{31}{30} \ gallons \ \ Or \ \ 1\frac{1}{30}\ gallons[/tex]
Hence Neil has left with [tex]1\frac{1}{30}\ gallons[/tex] of paint.
