Answer:
Explanation:
Given
Total volume of tank [tex]V=60\ L\approx 60\times 10^{-3}\ m^3[/tex]
Suppose a is the side of cubical tank
volume of cubical tank [tex]a^3[/tex]
[tex]a^3=60\times 10^{-3}[/tex]
[tex]a=3.909\times 10^{-1}\ m[/tex]
[tex]a=0.39\ m[/tex]
