Answer:
D= - 12sin(π/12)(t) + 68
Step-by-step explanation:
Let temperature D in terms of number of hours t be given as:
D= asinkt + 68
Now,
The difference between high and low temperatures is= 80-56= 24 °F
The period is= 24 hours
So, we have 2π/k= 24
Or, k= 24/2π
Now,
Let a= 12 hours
So, our equation becomes
D= 12sin(2π/24)(t) + 68
This is valid for 12 hours gap. If we want to implement for whole day then
D= - 12sin(π/12)(t) + 68
Put t=0
D= 68°F which is temperature at midnight
Put t=6
D= -12(1)+68
D= 56°F
Put t=18
D= -12(-1) + 68
D= 80°F