The maximum efficiency is 10%
Explanation:
The maximum efficiency of a machine is given by:
[tex]\eta=1-\frac{T_C}{T_H}[/tex]
where
[tex]T_H[/tex] is the temperature of the hot reservoir
[tex]T_C[/tex] is the temperature of the cold reservoir
For the machine in this problem, we have:
[tex]T_H=400K[/tex] is the temperature of the hot reservoir
[tex]T_C=360K[/tex] is the temperature of the cold reservoir
substituting, we find the max efficiency:
[tex]\eta=1-\frac{360}{400}=0.1[/tex]
So, the efficiency is 0.10 (10%).
Learn more about temperature:
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