Answer:
172.05 Rounded to 172.1
Explanation:
Using the following formula for the area of a regular pentagon
[tex]A=\frac{1}{4} \sqrt{5(5+25)}a^2[/tex]
[tex]A=\frac{1}{4} \sqrt{5(5+25)}10^2[/tex]
The Area of a regular pentagon will be "172.1 cm³". To understand the calculation, check below.
According to the question,
Side length (a) = 10 cm
We know the formula,
Area of Pentagon = [tex]\frac{1}{4} \sqrt{5(5+25) a^2}[/tex]
By substituting the values, we get
= [tex]\frac{1}{4} \sqrt{5(5+25) (10)^2}[/tex]
= [tex]\frac{1}{4} \sqrt{5(30) 100}[/tex]
= [tex]\frac{1}{4} \sqrt{150\times 100}[/tex]
= 172.05 or,
= 172.1 cm³
Thus the above answer is correct.
Find out more information about regular pentagon here:
https://brainly.com/question/858867
