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The radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the organism dies, after which it decays to stable carbon-12 at a rate proportional to the amount of carbon-14 present, with a half-life of 5551 years. Suppose C(t) is the amount of carbon-14 present at time t.

(a) Find the value of the constant kk in the differential equation C′=−kC.

Respuesta :

Answer:

k-0.000125

Step-by-step explanation:

Given that the radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the organism dies, after which it decays to stable carbon-12 at a rate proportional to the amount of carbon-14 present, with a half-life of 5551 years.

[tex]C' = -kC\\\frac{dC}{C} =-kdt\\ln C = -kt+C_1[/tex], where C_1 is arbitrary constant.

Or [tex]C(t) = Ae ^{-kt}[/tex]

To find K.

C(t) = 1/2 C when t = 5551

i.e. A will become A/2 in 5551 years

[tex]A/2 = Ae^{-5551k} \\ln 0.5= -5551k\\k = 0.000125[/tex]

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