Answer:
4.
a) [tex]4x^4-4x^3-16x^2+16x[/tex]
b) [tex]4x^4-4x^3-16x^2+16x[/tex]
5. Yes
Step-by-step explanation:
The distributive property is:
[tex](a+b)(c+d)=ac+ad+bc+bd[/tex]
It can be extended to a lot of terms as well.
We will use this to multiply both of the probelms shown.
4 a)
[tex](4x^2-4x)(x^2-4)=(4x^2)(x^2)-(4)(4x^2)-(4x)(x^2)+(4x)(4)=4x^4-16x^2-4x^3+16x=4x^4-4x^3-16x^2+16x[/tex]
The answer is [tex]4x^4-4x^3-16x^2+16x[/tex]
4 b)
[tex](x^2+x-2)(4x^2-8x)=(x^2)(4x^2)-(8x)(x^2)+(x)(4x^2)-(8x)(x)-(2)(4x^2)+(2)(8x)=4x^4-8x^3+4x^3-8x^2-8x^2+16x=4x^4-4x^3-16x^2+16x[/tex]
The answer is [tex]4x^4-4x^3-16x^2+16x[/tex]
5. Yes
