True or false: (a) For molecules with similar molecular weights, the dispersion forces become stronger as the molecules become more polarizable. (b) For the noble gases the dispersion forces decrease while the boiling points increase as you go down the column in the periodic table. (c) In terms of the total attractive forces for a given substance, dipole–dipole interactions, when present, are always greater than dispersion forces. (d) All other factors being the same, dispersion forces between linear molecules are greater than those between molecules whose shapes are nearly spherical.

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Answer:

A ,B- false

C,D- true

Explanation:

Dipole forces always lead to stronger attraction and boiling points than dispersion forces. When linear molecules are involved, they often posses greater dipole forces and higher boiling points. Linear alkanes posses higher boiling points than branched alkanes.

The dispersion force and the dipole force has been the attractive forces that result in the formation of bond within the molecules and result in the change in the properties of the compounds.

The dipole force is a strong force and results in a higher boiling point.

The statements regarding the forces are:

(a) For molecules with similar molecular weights, the dispersion forces become stronger as the molecules become more polarizable.

The statement is true.

(b) For the noble gases the dispersion forces decrease while the boiling points increase as you go down the column in the periodic table.

The statement is true.

(c) In terms of the total attractive forces for a given substance, dipole-dipole interactions, when present, are always greater than dispersion forces.

The statement is false.

(d) All other factors being the same, dispersion forces between linear molecules are greater than those between molecules whose shapes are nearly spherical.

The statement is true.

For more information about the dispersion force, refer to the link:

https://brainly.com/question/20514601