Respuesta :
Answer:
A .55
Step-by-step explanation:
Given that Leroy and Fred play chess at a club every Wednesday. The probability that Leroy will lose is .3, that he will stalemate is .5, and that he will win is .2. The probability that Fred will lose is .25, that he will stalemate is .4, and that he will win is .35.
lose stale win
Leroy 0.3 0.5 0.2
Fred 0.25 0.4 0.35
Probability that atleast one wins = Prob Leroy wins + Prob fred wins - prob both wins
(using addition theorem on probability)
But prob of both winning is 0
Hence required prob = 0.2 + 0.35 = 0.55
Option a is right
