Calculate the magnitude of the flux of a constant electric field of 5.00 N/C in the z-direction through a rectangle with area 4.00 m2 in the xy-plane. (a) 0 (b) 10.0 N m2/C (c) 20.0 N m2/C (d) more information is needed

Respuesta :

Answer:

The magnitude of the flux is  [tex]2.00 N m^2/C[/tex]

Explanation:

The electric flux through a planar area is defined as the product of electric field and the  component of the area perpendicular to the field.

Electric flux = Electric field * Area * (angle between the planar area and the electric flux)

The equation is

[tex]\phi = E A cos(\theta)[/tex]

Where:

[tex]\phi[/tex]is the Electric Flux

A is the  Area

E is the Electric field

[tex]\theta[/tex] is  angle between a perpendicular vector to the area and the electric field

Now substituting the values,

[tex]\phi = 5.00 \times 4.00 \times cos(0)[/tex]

[tex]\phi = 5.00 \times 4.00 \times 1[/tex]

[tex]\phi = 2.00 N m^2/C[/tex]