Answer:
C. .556
Step-by-step explanation:
Given that you have a rather strange die: Three faces are marked with the letter A, two faces with the letter B, and one face with the letter C. You roll the die until you get a B.
Probability of getting A = [tex]\frac{3}{6}[/tex]
Probability of getting B = [tex]\frac{2}{6}[/tex]
Probability of getting c = [tex]\frac{1}{6}[/tex]
Each throw is independent of the other
the probability that the first B appears on the first or the second roll
= P(B) in I throw +P(B) in II throw
= P(B) in I throw + P(either A or C) in I throw*P(B) in II throw
=[tex]\frac{2}{6}+\frac{4}{6}*\frac{2}{6}\\=\frac{5}{9} \\=0.556[/tex]
Option c is right
