Answer:
5.3 s
Explanation:
[tex]T_{e}[/tex] = Time period of simple pendulum on earth = 2.00 s
[tex]T_{m}[/tex] = Time period of simple pendulum on mars
[tex]g_{e}[/tex] = acceleration due to gravity on earth = 9.8 ms⁻²
[tex]g_{m}[/tex] = acceleration due to gravity on mars = 3.71 ms⁻²
[tex]L[/tex] = length of the pendulum
we know that, time period of pendulum is given as
[tex]T = 2\pi \sqrt{\frac{L}{g} }[/tex]
So
Time period of pendulum is inversely related to acceleration due to gravity
hence
[tex]\frac{T_{m}}{T_{e}} = \frac{g_{e}}{g_{m}}\\\frac{T_{m}}{2} = \frac{9.8}{3.71}\\T_{m} = 5.3 s[/tex]
