Respuesta :
Answer:
I believe the answer is Bromine forms covalent bonds because it has many electron shells, but neon has only two electron shells and is tightly bound to its electrons.
Explanation:
valence electrons are the outermost shell, so when you go through keeping that in mind it helps you find the right answer
Bromine forms covalent bonds because it has seven valence electrons, but neon has eight valence electrons and already fulfils the octet rule.
Atomic number of Bromine (Br) is 35. The electronic configuration of Br is 2,8,18,7. Br has 7 valence electrons. It requires 1 electron to complete it octet or noble gas configuration. So, Br forms covalent bond.
Atomic number of Neon (Ne) is 10. Electronic configuration is 2,8. Neon have completely filled electrons in its outer most shell. so, neon is highly stable, as the result, neon not easily react with other elements. Therefore, neon doesn’t form covalent bond.
Thus, we can conclude that, Bromine forms covalent bonds because it has seven valence electrons, but neon has eight valence electrons and already fulfils the octet rule.
Learn more about covalent bond here:
https://brainly.ph/question/10073355