Answer:
[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex] m/sec
Explanation:
According to the question
[tex]\frac{1}{2}I\omega^2=\frac{1}{2} mv^2[/tex]
\omega= angular velocity = 14 spins per sec
I= MOI of the spinning eel= 0.5mR^2
m= mass of eel
v= linear velocity of eel.
[tex]\frac{1}{2}0.5mR^2\omega^2=\frac{1}{2} mv^2[/tex]
solving for v in the above equation we get
[tex]v=\sqrt{\frac{R^2\omega^2}{2} }[/tex]
now \omega in radians = 14 rev/sec×2π radian/rev= 28π radian/sec
value of radius is not provided in the question
therefore we get
[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex]
