Respuesta :
Answer:
(a) The work required to move the crate = 7150 J
(b) The Work required to move the crate vertically = 6000 J
Explanation:
(a) Frictional Force: These is the force that tend to oppose the motion of two bodies in contact.
Work required to move the crate = work done against friction + work required to move it through a distance of 5.0 m.
Wr = Wf + Wd
Where Wr = work required to move the crate, Wf = work done against friction, Wd = work required to move the crate through 5.0 m
Given: Wf = friction force × distance = 230×5 = 1150 J
and Wd = force × distance = 1200×5.0 =6000 J.
Substituting these values into equation 1
Wr = 6000 + 1150
Wr = 7150 J
Therefore the work required to move the crate = 7150 J
(b)
Work required to move the crate vertically = mgh
or
Work required to move the crate vertically = Wh................ Equation 2
Where W = weight of the block, h = vertical height
Given:W = 1200 N, h= 5.0 m
Substituting these values into equation 2
Work required to move the crate vertically = 1200×5
Work required to move the crate vertically = 6000 J
The work required to a given object in the horizontal and verticle direction is 7150 J and 6000 J respectively.
From the formula,
[tex]W = Wf + Wd[/tex]
Where,
[tex]W[/tex] - required to move object
[tex]W_f[/tex] - work done against friction = 230 N x 0.5 m = 1150 J
[tex]W_d[/tex] - work requred to move object to [tex]d[/tex] distance = 1200×5.0 = 6000 J.
Put the values in the formula,
[tex]W = 1150 +6000\\W = 7150 \rm \ J[/tex]
B) Work in the vertical direction,
[tex]W = mgh[/tex]
Where,
[tex]mg[/tex]- weight = 1200 N
[tex]h[/tex] - height = 0.5 m
Put the values in the formula,
[tex]W = 1200 \times 5 \\W = 6000\rm \ J[/tex]
Therefore, the work required to a given object in the horizontal and verticle direction is 7150 J and 6000 J respectively.
To know more about work in the verticle direction,
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