Answer:
e) Shamika= 224 balloon, Crystal= 112 balloon, Aliya= 114 Balloon.
f) We know,Crystal sold "b" balloon
Aliya sold (b+2) balloon
Shamika sold 2b balloon.
As per data given in question part c that each balloon cost $2 and Total cost of balloon is $900.
Now, solving to find how much each student sold balloon at school´s winter dance.
As we know total cost is $900 and each balloon cost is $2.
∴ Total cost= [tex]Total\ quantity \times cost\ of\ each\ unit[/tex]
Total quantity= [tex]{b+(2+b)+2b}[/tex]
∴ [tex]\$ 900= {b+(2+b)+2b}\times \$ 2[/tex]
Once we solve, we will get the value of b as 112 balloon, which is the number of balloon sold by Crystal.
Substituting the value of b in the equation of Aliya and Shamika, we will get the number of balloon sold by them.
Which is 114 and 224 respectively.
Step-by-step explanation:
Given: Crystal sold "b" balloon
Aliya sold (b+2) balloon
Shamika sold 2b balloon.
As per data given in question part c that each balloon cost $2 and Total cost of balloon is $900.
Now, solving to find how much each student sold balloon at school´s winter dance.
As we know total cost is $900 and each balloon cost is $2.
∴ Total cost= [tex]Total\ quantity \times cost\ of\ each\ unit[/tex]
Total quantity= [tex]{b+(2+b)+2b}[/tex]
∴ [tex]\$ 900= {b+(2+b)+2b}\times \$ 2[/tex]
Opening the parenthesis.
⇒[tex]\$ 900= (b+2+b+2b)\times \$ 2[/tex]
⇒[tex]\$ 900= 2+4b \times 2[/tex]
Dividing both side by 2
⇒ [tex]\$ 450= 2+4b[/tex]
Subtracting both side by 2
⇒ [tex]\$ 448= 4b[/tex]
Cross multiplying
∴[tex]b= \frac{448}{4} = 112[/tex]
∴ b= 112.
Hence, we can say Crystal have sold 112 balloons.
Next subtituting the value of "b" in the equation for Aliya and Shamika to get number of balloon they have sold.
We know, Aliya sold b+2 balloons
∴ Aliya sold= [tex]112+2= 114\ balloon[/tex]
Aliya sold 114 balloon.
We know, Shamika sold 2b balloons
∴[tex]2\times 112= 224 balloon.[/tex]
Shamika sold 224 balloon.
