Respuesta :
Answer:
h = 10 m
Explanation:
given,
mass of platform = 50 Kg
Kinetic energy = 5000 J
height from which the diver dove = ?
taking acceleration due to gravity = 10 m/s²
using conservation of energy
Kinetic energy is converted into mechanical energy
K.E = P.E
K.E = m g h
5000 = 50 x 10 x h
500 h = 5000
[tex]h = \dfrac{5000}{500}[/tex]
h = 10 m
The height from which the diver dove is equal to h = 10 m
The height from which the diver drove is mathematically given as
h=10m
What is the height from which the diver drove?
Question Parameters:
A 50-kg platform diver hits the water below with a kinetic energy of 5000 Joules
Generally, the equation for the Kinetic energy is mathematically given as
K.E = P.E
Therefore
K.E = m g h
5000 = 50 x 10 x h
500 h = 5000
In conclusion,the height is
[tex]h = \frac{5000}{500}[/tex]
h=10m
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