Answer:
See below explanation
Explanation:
Checking the reduction potencials:
Zn⁺²/Zn° , E° = -0.76 V
Fe⁺²/Fe° , E° = -0.44 V
For which Fe⁺² will be the ion that will reduce, and Zn° will lose electrons
ANODE: Zn° ⇄ Zn⁺² + 2e⁻
CATODE: Fe⁺² + 2e⁻ ⇄ Fe°
NET CELL REACTION: FeSO₄ (ac) + Zn° ⇄ Fe° + ZnSO₄ (ac)
In the external circuit, electrons will migrate from anode (Zn|Zn⁺²) to catode (Fe|Fe⁺²), and in the salt bridge; anions migrate from Fe⁺²|Fe compartment to Zn|Zn⁺² compartment