Answer:C 0.12 V
Explanation:
Given
Concentration of [tex]Fe^{2+} M_1=0.40 M[/tex]
Concentration of [tex]Ni^{2+} M_2=0.002 M[/tex]
Standard Potential for Ni and Fe are [tex]V_2=-0.25 V[/tex] and [tex]V_1=-0.44 V[/tex]
[tex]\Delta V=V_2-V_1-\frac{0.0592}{2}\log (\frac{M_1}{M_2})[/tex]
[tex]\Delta V=-0.25-(-0.44)-\frac{0.0592}{2}\log (\frac{0.4}{0.002})[/tex]
[tex]\Delta V=0.12\ V[/tex]